Expression help 1

Try this instead.


if(length<100)(1)else(if(length<200)(2)else(if(length<300)(3)else(4)))

your original expression would only output 1 or 2. As soon as the value of length was over 100 it would not get any further down the chain if if statements as 200 is still greater than 100 therfore the result is still 2.
Hope that makes sense.

You'll have to make your positioning of your first hole and the array spacing a function of the output of this expression to ge the holes equispaced.

Cheers,


Mark Benson
Aerodynamic Model Designer

try

if (legth>100)(2) else if(length>200)(3) else if(length>300)(4)else(1)

that should be all )

Excellent! Thank you MSPBenson, that worked a treat!

Vitulaaak, I tried yours too but it didn't seem to work

Mark Noyce
Senior Design Engineer/CAD co-ordinator

well,funny..i tried it again and
if(cond>20)(10) else if (cond<20)(20)else(15)

worked fine...

vitulaak,
your first expression can not work, because if the length is say 350, which is > 100 (your first condition) then it inserts 2 holes and does not go farther - the condition (>100) was satisfied).
Your second expression is different - you should see (15) only if the cond=20, because the first two parts (>20, <20) cover all remaining (real) numbers.

well, i just meant the syntax...if you have descending order 300.200.100, then it works and you dont have to use the number of brackets