Recent content by 1234910

red/orange is corrosion.

we had taper roller bearing used in entry guide roll failed as shown in photograph, entry guide roll too has broken from one of it's collar . do suggest possible reasons. http://files.engineering.com/getfile.aspx?folder=f5637878-24df-4f0d-8b6a-66fd0ba08d3e&file=taper_roll.pptx

YES it's a corrected gear , with addendum modification coeff as = 0.33

3DDAVE PCD OF TWO PINS - 450 MM . SO RADIUS = 450/2 MM .

THANKS

PCD OF TWO PINS - 450 MM . SO RADIUS = 450/2 MM .

HOW TO FIND BASE TANGENT LENGTH OF DOUBLE HELICAL GEAR WITH 199 TEETH .NORMAl module - 8 , pressure angle - 20 degrees , formula and calculation thanks

HOW TO FIND BASE TANGENT LENGTH OF DOUBLE HELICAL GEAR WITH 199 TEETH .NORMAl module - 8 , pressure angle - 20 degrees , formula and calculation thanks

OK

SOME PHOTOGRAHS ARE SENT http://files.engineering.com/getfile.aspx?folder=7a65a1e5-62a5-49a6-8596-c7dd254a4cfa&file=SHEAR_PIN__BREAKAGE.pptx

oh,yes i was thinking about safety factor only ,i needed clarification, for the word effective influence . thanks and regards

rolmec what does effective influence of 1.5 means , which you have taken in your calculation .

Since the pin was very tight inside t he bush , with great difficulty it came out ,so freeting ? if their is looseness between the pin and bore than freeting will come into play , if i am not wrong .

Given nominal torque & geometrics etc.: 9550*400*2/(306*0,395*452,4) = 140 N/mm² What does 452.4 inidcates i nthe above equation ? do suggest and what does 140 N/sqmm indicates ? Given fy with 235 N/mm² & γF to 1,5 & shear: 235/(1,5*sqrt(3)) approx. 90 N/mm² give the specific formula ...

if we take endurance strength of material for ST -37 material ,it is = 222 N/ sqmm . Than breaking load on pin = stress x notch area = 222 x 3.14 /4 x 24 x 24 since notch dia is 24 mm = 81388.8 N =81.3888 KN...