Continue to Site

Eng-Tips is the largest engineering community on the Internet

Intelligent Work Forums for Engineering Professionals

Register Log in
  • Congratulations SSS148 on being selected by the Eng-Tips community for having the most helpful posts in the forums last week. Way to Go!

Recent content by Driekes

  1. Driekes

    Force due to shrinkage

    Ok, Thank you both very much for the replies ! It would be very good if the steel is unaffected or compressed less than .5mm
  2. Driekes

    Force due to shrinkage

    Well our test data show the LDPE ring exerts 5-600 N on the steel ring, which would make it shrink an extra 0,2mm. 0,5 would be to much that`s why I need to calculate the worst case. The LDPE is 3mm thick, the steel 2mm.
  3. Driekes

    Force due to shrinkage

    Hi guys, A (hopefully) simple question but I can`t find a conclusive answer. Let`s say I have a LDPE ring with a steel ring inside. Both are placed in a room at -30°C (coming from +20°C). Because the shrinkage of LDPE is bigger than the shrinkage of steel, the LDPE ring will exert a force on...
  4. Driekes

    Calculating displacement and clamping force

    Hi guys, I`ve been stuck at this for days, maybe time to get some other opinions. I work in the pipe closure industry and for a next project we need a bigger clip to secure our bevelprotectors (ring). A bevelprotecor is something that is placed inside a pipe, where a plug has been installed...
See more

Part and Inventory Search

Back
Top Bottom