aafuni / zekeman,
i think you may be right. I will try experimenting with slower acceleration speed to start. Although this may prove tricky with our setup at present.
desert fox - yes the plate is supported by rollers along it's travel path. So you are correct about the reaction being less...
Thanks for the input MintJulep.
When I first tried this problem, I converted my motor torque to force. (T = F*r) where r is radius of the wheel.
Then using the equation in the OP with an f value of 0.0077m (which is for hard rubber on steel I believe) worked out the minimum Normal force...
What I was actually aiming for was to increase the normal force. ie to use a larger cylinder.
I was just looking for a way to determine how much force is required.
I'll try playing with the equations mentioned.
Thanks again.
Thanks for all the replies folks.
The wheel is only activated after contact is made. A roller on the top is tricky for various other reasons.
Am I right in thinking that a solution would have to account for contact area of the wheel? As surely a wider tyre would have more grip.
See if this helps at all.
Sorry for the quality but there's only so much you can do with ms paint...http://files.engineering.com/getfile.aspx?folder=0cb7221a-706d-4eb2-8f1f-36dbe8f63dd5&file=accel_cyl.JPG
Thanks for the reply.
The wheel is made of a patterned rubber, like a car tyre. The plate is steel. I can't do anything to the plate but could change the wheel tyre, however I don't know if that would be much help.
Hi guys, hopefully someone here knows how to tackle this. I've been trying to work it out for a while.
We have a machine which moves heavy plates with a spinning wheel. The wheel presses the plate from under then spins to drive the plate onto a rack. Sometimes the wheel doesn't have enough grip...
