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Recent content by Tygra_1983

  1. Tygra_1983

    Natural Frequencies in ETABS

    Do you have any ideas what could be the problem then, Greg? I mean, I just build the model and run the modal analysis. EDIT: The reason there appears no shape is because it is oscillating in the direction into the screen, lol. I just discovered it.
  2. Tygra_1983

    Natural Frequencies in ETABS

    In modes 1,3,4,5 there is no shape. Etabs shows no displacement at all: Here, are mode shapes 2, 6, 7 and 8.
  3. Tygra_1983

    Natural Frequencies in ETABS

    Dear all I am trying to simply compute the natural frequencies of a 4 storey structure in ETABS. I am also trying to validate them in MATLAB. However, I am getting drastic differences in the results. This is strange because a couple of years ago I did a dynamics of structures coursework...
  4. Tygra_1983

    Help in ETABS Regarding the Storey Stiffness Option

    Hi all, I have download the 30 day trial for ETABS and practising with it. I am trying to find the storey stiffness in my model. To do this you go to Tables > Analysis Results > Structure Output > Other Output Items >Story Stiffness. However, the table comes out completely blank, as you can...
  5. Tygra_1983

    Calculating Axial Load in a Tire Beam

    Here are the axial forces from thew SAP2000 model Here, are the bending moments. EDIT: I have gone for the apex being pinned, and from this I get the answer I was looking for. I have been following a book with a similar example and I thought the apex was fixed. rb1957, you answer of 20.47...
  6. Tygra_1983

    Calculating Axial Load in a Tire Beam

    Sorry, here is the equation with units: To clarify, the main diagonal structure is fixed at the apex. The tie beam is pinned. Also, because of symmetry I am only considering one side in the calculation. The load on the frame is 4kN/m. The upwards force is the vertical reaction at the pin of...
  7. Tygra_1983

    Calculating Axial Load in a Tire Beam

    Hi Greg, Hopefully, this diagram will clear some things up. The long equation is the moments taken about the apex. Sorry I see now, I made a couple of typos to the original equation. I am assuming anti-clockwise as positive about the apex, so yes, the first two terms are negative, but end...
  8. Tygra_1983

    Calculating Axial Load in a Tire Beam

    Hi, I have the following example where by I am trying to calculate the axial force in the tie beam: The geometry is: width = 10m, height = 8 metres, angle = 57.995 degrees. The diagonal members are 9.43m (sqrt(89)) And these are the support reactions: If the tie beam is fully fixed I can...
  9. Tygra_1983

    My Meshed Slab Does Not Transfer Load to Supporting Beams (SAP2000)

    Dear all I have this simple structure in SAP2000: I want the self-weight of the slab to transfer to the beam at the slab edges. The self-weight = 25 kN/m^3*0.2m = 5 kN/m^2. I have done the appropriate meshing, but the self-weight of the slab does no seem to be transferring to the beams...
  10. Tygra_1983

    Correct Displacements, but incorrect moments using the DSM for Structure

    Thanks for you reply, rb1957. After much staring at the screen and wondering why (lol) I have realised that you have to add on the fixed end forces/moments to the vector A in the code. Thus, for member 2 we get Member2_forces = [ A(1) A(2) + 600 A(3) + 4000 A(4) A(5) + 600 A(6) - 4000]...
  11. Tygra_1983

    Correct Displacements, but incorrect moments using the DSM for Structure

    Hi rb1957, 1) So, these are the fixed end moments. the UDL is 30 kN/m. Thus, for member 1 that is 10m long, the force at the node is 30*10/2 = 150 kN, and the moment is 30*10^2/12 250 kNm. For member 2 that is 40m long, the force at the node is 30*40/2 = 600 kN, and the moment is 30*40^/12 =...
  12. Tygra_1983

    Correct Displacements, but incorrect moments using the DSM for Structure

    Dear all, I have the following structure with its loading that I am trying to solve I am using the stiffness method, and my MATLAB code is below: clear, clc, close all % Structural properties E = 2.1E+08; I = 1022000/100^4; A = 620/100^2; EI = E*I EA = E*A alpha = atand(30/40) L1 = 10; L2...
  13. Tygra_1983

    Load Distribution on Elements

    Its just another phrase to emphasize that He will never stop taking care of you.

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