Hi there,
I calculated single shear stress in a pin as:
Diameter of Pin = 100mm
Material: IS:2062
Load / Force = 16000N
so
Shear Stress = Force/Area
=16000N/7854mm2
=2.04 N/mm2
Shear Stress =2.04 MPa
Now,
Shear Strength(Yield) of IS:2062 = Tensile Strength(Yield) x...