@LittleInch Thanks for letting me know I am new to this forum page, it was a separate question so I thought I should make a new thread, since it also has some different details.
The type of flow I'm assuming would be a partially full flow around 64% full if I use that 900 gpm is coming into the...
How can I translate the height of water in a box to the velocity needed for a water to enter a pipe? Assuming all this work is being done by gravity, no pumps.
I have came to the conclusion of the Bernoulli Equation to get sqrt(2*g*h) = v^2
Would this actually be able to translate into the...
I think we got a little off track, I was originally creating a basin with 12" drain coming from the bottom side of the basin, it comes straight out with a constant slope of 10 inches over 120 ft. This basin would have 900 gpm flowing into it from around anywhere from 5 min to an hour. I believe...
Here is a little draft I came up with for what I am thinking of. The inverts of both 12" pipes are at the bottom of both basins, water would only be going into one basin or the other not at the same time with a 2.4 inch drop between the connections. I changed the one I was talking about before...
@LittleInch Using an air gap as means for a backflow preventer, figured a concrete box would be the easiest way to catch the water. Also gives us a little something to help if anything goes wrong.
Only reason I'm worried is we had a similar well outputting 900 gpm with a 12 inch drain that...
Hello!
I have a concrete box that is going to be filled with water at 900 gpm, the dimensions are 7' * 5' and a 3' depth. I am planning on installing a 12" drain pipe made of PVC coming from the side of the concrete box, it daylights 120 ft out with only a .838 ft drop (about 10 inches). Will...
