I appreciate all your comments.
I was working out for a positive displacement pump, and the datasheet included two types of efficiency, which are mechanical and volumetric.
I thought these two types should be combined but not really sure if I was doing it correctly.
The multiplication of those...
Hi, I am a graduate-level mechanical engineer.
I am working out a hydraulic power using the equation below:
(Q * P) / (600 * e) = kW
Where, Q: Flow rate (L/min), P: Pressure (bar), e: Pump efficiency
I wonder if the pump efficiency 'e' is the total pump efficiency.
I believe there are a...
@1503-44,
I am determining the valve closure time using the pump flow rate because I've got no idea how to calculate the flow rate from the accumulator to the valve actuator.
Would you mind having a look at the calculation below to see if the valve can be closed within 30 sec and if there is...
@LittleInch
Thanks for the huge help. I think now I am getting to know about the HPU!
If there are any calculation methods or ways to verify how much a pump can be smaller to utilise an accumulator, should it be tested in laboratories or performance tests?
I also wonder how much smaller pump...
I appreciate your help.
@1503-44, for clarification,
In your comment, which states that "The accumulator only provides the volume of fluid needed to close the valves." and "The flow rate 0.0225 L/s determines how fast the swept volume is supplied.", I wonder about the relationship between the...
Hi, @LittleInch and 1503-44. Thank you for your kind reply.
I cannot upload the diagrams and stuff, directly relating to the ongoing project due to security reasons.
The system is analogous to the article written below...
Hi, I am a 6 months experienced graduate mechanical engineer in the offshore oil and gas industry.
Currently checking the hydraulic power unit system calculation, but have a few questions in relation to valve closure time.
I have the valve actuator swept volume data (2.019 L), and it shall be...
