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Haha. Thx BigInch. I will keep on that link you posted. There are actually quite a few piping jobs there. Whether they will hire a grad is a different story. lol.

Thanks ZDAS04, your comment was very informative. You see I always thought the facilities engineering was basically the reliability department in terms of vibration monitoring etc. which I am not interested in. However, from what you are saying, it is something that you kind of work yourself...

Thanks for the reply Pennpiper.... I was aware of the that department layout already and I am interested in all of it. The least being the Piping Materials guy; but that still has it's interesting points. I really want to get to doing project management with a good foundation in piping...

I should also say that I really do enjoy applied fluid mechanics, stress analysis and maybe not so much heat transfer.... although I'm still good at it. I have taken classes in Computational Fluid Dynamics and Heat Transfer, Advanced Thermofluids with emphasis on Vector Calculus...

Hey guys, I am going to be graduating in 6 weeks in Mechanical Engineering from the University of Victoria, in British Columbia Canada. I was hoping to get some advice on the best way to approach getting into piping engineering. I have a few years CAD experience using Solidworks and Inventor...

They do sell displacement sensors....

Got it to work Rybose.... I just differentiated twice like you suggested. The only reason I didnt before was because it was a numerical solution I obtained and you cant differentiate that. Your method made my results come out bang on. Thanks for keeping in touch.

Basically Rybose, my relative acceleration plot is very similar to your absolute acceleration plot. In fact, after the first peak at 48.9 g's... it is EXACTLY the same. This of course makes sense as the base is considered stationary after that point. I have attached a file comaring the...

Thats what I thought too. Yes, I am using the same identity as x" = z" + y" So here is my derivation: Solve for Relative Acceleration: z" = -h(t)-2*c*w*z'(t)-w^2*z(t) where: h(t) = the unit step function for the sawtooth (one pulse in this case to match yours) z" = relative...

Rybose... if you read this... I cant seem to get the absolute acceleration to come out right. With the substition of z=x+y for the accleration... I solve for relative acceleration. When i try to us this z=x+y relationship to bring out the absolute acceleration of the mass.... its...

I have read throught that Steinburg book and when it comes to shock anaylsis ... it is very basci and it even says so in the book. It says... there are 3 ways to analyse shock isolation... it covers the first too with some equations and at the end it says if the isolators are non-linear...

NASTRAN... surprise? how so...

SPONGEBOB..... sorry I idnt read enough... got it at 0.05. But 0.4" to attenuate a 50g shock is very unlikely. how did you arrive at that? I got 35mm displacmenet with those numbers which only isolates to 40g and dies out after that...

SPONGEBOB what was your total damping ratio for the system for that set-up with a 4" deflection?

Thanksm for the input spongebob... that gives me more confidence in my results.

MY DISPLACEMENT PLOT IS THE SAME HOWEVER, WHEN I SIMPLY PUT IN ONE SHOCK PULSE INSTEAD OF 3

NEVER MIND THE DISPLACEMENT PLOT ISNT EXACTLY THE AME AS THERE IS ONLY ONE SAWTOOTH PULSE CONSIDERED IN THE THE MATLAB MODEL.

MY DISPLACEMENT PLOT IS THE SAME TOO... BANG ON

RYBOSE.. is that the GUI that cost $40 to use the matlab scripts? If so, im will subscribe. Its worth it to prove my model.

RYBOSE... I dont wanna bug you too much, you have already been so helpful... but if you want, could you run the same simulation with more damping. Realistaclly, each rubber/neprne bushing has a damping ratio of 0.05 and when you have more than one inline, the damping ratios are added. So...