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Thank you for all your replies, and help.

I am afraid I do not understand you. Yes, when scaling this body, the center of the scaling should remain fixed. The problem is that up until now I have been using volume centroid as the center of the scaling. Now, it looks like volume centroid of the box that covers this body could be used too.

Hi rb1957, I am not sure I understood you. By scaling a volume its support surface underneath moves also.

By scaling it, the bottom surface beneath the body also moves, with the new scaled object.

The Photos did not appear in the upper initial post. I apologize for that. Here are the there photos that should have appeared up: http://files.engineering.com/getfile.aspx?folder=64801518-d4fe-46cb-a6a8-268c513a5d47&file=1.jpg...

Hi, I have a solid body (of a material of uniform density, for example steel), and I want to scale it by 2 times. As a center of scaling, I have always been using volume centroid, as its the same one as the center of the mass. Here is the preview of the body and its volume centroid: "VC" -...

Thank you rb1957. So I could use the general expression for elastic potential energy? : U(x) = (1/2) * k * x^2 k = (A*E)/L U(x) = (1/2) * ((A*E)/L) * x^2 ? So that's the expression for elastic potential energy of axially loaded column? The change in potential energy would be the derivative of...

Thank you for the reply, both of you. It should be "potential" energy, instead of "bending". Terribly sorry about that. So "an expression for potential energy and for the change in potential energy coming from the selfweight/or point load on top of the column" is the right sentence. @Buggar...

I am looking for an expression for bending energy and for the change in potential energy coming from the selfweight of a vertical circular solid column, or maybe from vertical point load on top of it. Any ideas where I could find these? Thank you.

Is anyone willing to show me some video tutorial, or even record it's own Ansys screen on buckling and lateral torsion check of a simple plain truss members: The amount of the compressional force on the left is not important, it can be any value (1,2,3 kN). The dimensions of the truss too -...

Understood. Thank you rb1957, BAretired, pax, I owe a couple of beers to all of you, for the help and patience you had. I wish you all the best.

Thank you for the reply rb1957. All four red lines in top view are contact lines. I just bolded them in order to be seen more clearly. I understood you about the moments calculation. But as W force in not perpendicular to the far right red axis, I need to decompose it into two forces - Wp and...

BAretired, are we neglecting one of Wind load resultants components (Wp)? F1 - resultant of the self weigh of object (dead load) F2 - resultant of outer, external surface load W - resultant of wind load Wn - component of W, normal to overturning axis Wp - component of W parallel to...

I am apologizing for the late reply. @ rb1957: There were two methods montioned in this post. One method was by - interesecting the lines of action of wind load resultant and objects mass resultant. And then summing those two vectors in the position where their lines of action intersected. The...

I made a mistake: yellow vector represents the resultant of the surface load. Not blue! Here is the image. Sorry for that. To bad this forum does not have an edit post function.

This is just an example I made up, not an actual object. I am trying to understand the concept in order to apply it to future actual objects. This will probably be some sort of table, let's say around 90cm (around 3 foot) in height, 260 cm in length (about 8,5 feet) and 160cm in width (about 5...

@BAretired: I owe you an apology. I mixed these two units. I am using metric unit system, so I could not distinguish the difference between the psi and psf. I used an online conversion and saw the relation between these two is huge. Sorry for that once more. @pax: English is not my maternal...

My apologizes for my late reply. I had some health issues, still do. @prex: Thank you. Do you mind if I disturb you a bit more? I did not understand that part when you spoke about sliding the forces. Is this what are you talking about: I slided horizontally the green vector from east to...

Thank you prex. But why I can not use this method: link to get the resultant (pink arrow) of the sum of orange (selfweight + external vertical load) arrow and green arrow (wind load)? In that way I will determine the point in which that resultant will act. I did not know about that vector...

Sorry I forgot the squares. Yes pythagoras theorem. And yes pink arrow (English is my second language, so purple and pink seemed the same to me. Now I see it is not). Main reason got me confused in this last part was an anchor point for the wind vector. It should be located (that anchor point)...