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Thank you all. Jraef, you are correct all that is provided is the MCA value on the chiller. I am performing a SC/Coor/AF study on the facility and my software requires a HP or kW rating. The chiler will slightly affect my SC results and could change an IE level in my AF analysis. Thanks.

Can someone confirm if my calculations are correct? I was given only the MCA of a chiller (571.3), it is applied at 480V and I want to convert MCA to HP. I divided the MCA by 1.25 to get 457A (assume this is the FLA). HP = V*I*eff*1.73*pf/746 I assumed eff=0.85 and pf=0.8 to get 345hp...

Thank you to everyone who commented. Much appreciated. Mike

Yes, I was given an available fault current at the secondary of the XFMR (by applying a fault at the secondary). I am looking for the available fault current on the primary (by applying a fault at the primary of the XFMR). So the second question, a primary fault if there is 32kA on the...

I agree, however that would not take into account the impedance of the XFMR.

Thanks for commenting. I see you took the FLAs on the primary and divided it by the impedance of the XFMR to get the fault current on the primary. By doing this don't you only take into account the XFMR?? What if there was other contribution from motors or generators? I am looking for a...

thread238-163018 In reference to Thread 238-163018. I am having trouble converting a secondary fault current to the primary of a transformer. I believe you can use either the PU method or the MVA method, however my results are coming out too small. Here the numbers I am using if it helps...