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  1. abaqususer1981

    Determine contact area

    Sorry but the only person who seems desesperate is you, chill and take your depression pills. Look, I don't want to waste my time with you but as a benefit to all the community let me say that my original question is quite clear: tension axial load + bending moment. The feedback from other...
  2. abaqususer1981

    Determine contact area

    Of course, contact between surfaces must not be frictionless.
  3. abaqususer1981

    Determine contact area

    Let's say you apply a vertical compressive axial load to the top of a column together with a horizontal load (with a smaller value). At the bottom the column has a baseplate (square in plan). If you apply these loads and let the column deform a lot you will start to see tensile forces at the...
  4. abaqususer1981

    Determine contact area

    Yes, Ac will be reduced so you have to iterate, new tension stresses, new Ac..... and it will converge to a non zero Ac or to a zero Ac.
  5. abaqususer1981

    Determine contact area

    If you have a lateral load applied to the top body (or this body suffers a rotation) and then it is stretched, the applied stress due to tension load is Nt/Ac, where Ac is the compressed area, which will be added to the stresses due to the bending moment. If the tensile stresses from the applied...
  6. abaqususer1981

    Determine contact area

    Well, then please rethink your statement: "If tension Nt exceeds W, the movable block will lift off and contact area = 0. " because this is what doesn't make sense and most importantly is wrong. If the load is tensile but the eccentricity of the bending moment is such that the section is...
  7. abaqususer1981

    Determine contact area

    I appreciate all the answers. Corus: that's just a very rude simplification to make in my opinion. If I wanted to do that there was no point of developing a spring-like element. Regarding other comments, please do not forget that the axial load is a tension load, not compression, so for an...
  8. abaqususer1981

    Determine contact area

    In particular, the stresses can be determine in elastic regime by: σ = Nt/At - M1*y/I - M2*x/I Know At is the contact area, but I don't think I is the inertia of the entire cross section of the block since only part of it is being deformed (opposes to deformation).
  9. abaqususer1981

    Determine contact area

    Hi corus! Thanks for your reply. The thing is I'm trying to develop a joint finite element (spring like element) that simulates the contact between two blocks (simulated by beam elements). So I need to know when the elements are separating apart and to know that I need to calculate the contact...
  10. abaqususer1981

    Determine contact area

    Imagine you have two block with square cross sections with side length a. One is fixed and cannot deform. The other is free to move and rotate. Both blocks have initially two surfaces in full contact and no sliding is allowed between these two surfaces. A bending moment in each principal...
  11. abaqususer1981

    Sharing variables between different subroutines

    @DanStro: For the intended purposes no I haven't. I'm struggling to see how they could become useful for changing the values of internal, but globally available, UEL variables used to check if we are at the first iteration of a given increment and update their value based on a boolean loop or to...
  12. abaqususer1981

    Sharing variables between different subroutines

    Just to add a note to my answer: My particular problem is to run three different subroutines that need to share global variables between them along the analysis using cpus=2. For instance: In the beginning of the analysis KW = 0, each time the UEL is called KW = KW + 1 until a new increment is...
  13. abaqususer1981

    Sharing variables between different subroutines

    Hi All! My particular problem is to run three different subroutines that need to share variables between them using cpus=2. I've tried using SAVE statement but it does not work with multiple cpus. I also tried writing and reading from temporary txt files but this solution is not general. In...
  14. abaqususer1981

    Update rotation matrices based on abaqus rotation nodal values

    Hi All! Imagine you have a two noded beam in space, defined by extreme nodes 1 and 2, see figure. To simplify, initially, the longitudinal axis of the beam, defined by the unit vector of the line that connects the nodes 1 and 2, is coincident with the X axis of the global coordinate system...

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