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- Users: GianlucaTempesta
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Force Required to Open Door
Thank you so much!!!- GianlucaTempesta
- Post #9
- Forum: Fluid Power engineering
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Force Required to Open Door
Hello, this door in fitted on a civil construction! Kind Regards- GianlucaTempesta
- Post #7
- Forum: Fluid Power engineering
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Force Required to Open Door
Weight(kg) 1400 D (mm) 390 D1(mm) 880 Lb(mm) 1270 L(mm) 2500 s(mm) 90 Rv (N) 3433.5 Rh (N) 6867 R (N) 7677.539401 C.attr 0.01 Mattr (Nmm) 174421.8 F (N) 69.76872 teta 95 teta transient 1 stroke actuator 200 vel min 7 t totale 30.57142857 t constant (s) 28.57142857 t transient...- GianlucaTempesta
- Post #5
- Forum: Fluid Power engineering
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Force Required to Open Door
Hello Ted, thank you so much for your reply. So I have this situation. Weight of door 1400 Kg Dimensions 2500x2500 mm Door is hinged on a vertical side Hinges are working on ball bearings. Opening angle from 0° to 95° t1 = 2 sec t2 = 30 sec teta 1 = 1 deg teta 2 = 94 deg I'm going to open and...- GianlucaTempesta
- Post #3
- Forum: Fluid Power engineering
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Force Required to Open Door
thread1083-438231 @hydtools I found this formula, F = (I*(95 - theta)*pi)/(180*r*t*(20-t)) Could you explain how did you get it Thank you in advance. Kind Regards- GianlucaTempesta
- Thread
- Replies: 8
- Forum: Fluid Power engineering
