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  1. Metastable

    Analog error angle between two sine-cosine potentiometers

    thread240-291259 in 2011 never arrived at an elegant solution. I think this is such a solution, using two analog multiplies: If C1, S1 are the cosine and sine outputs of potentiometer 1, and C2, S2 are from pot 2, then C1 * S2 - S1 * C2 = sine of error angle. Similarly, S1 * S2 + C1 * C2 =...

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