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  1. DerbyEngineer

    Why do textbooks say Plane Stress is for thin components?

    Thanks rb1957. I think I've got it now [smile]
  2. DerbyEngineer

    Why do textbooks say Plane Stress is for thin components?

    Hi everyone, I'm struggling with another concept - this time plane stress... From my understanding, plane stress occurs when in-plane loads are applied to a structure such that stress through the thickness is zero. So far, so good. However, my textbooks state that plane stress occurs in thin...
  3. DerbyEngineer

    Rectangular bar in torsion - why are the shear stresses at the corners zero?

    Thanks all, but I still don't understand despite all the diagrams, scanned textbooks, explanations etc. rb1957 - I agree, it makes intuitive sense that shear stress in the corners has to be zero to prevent it having to suddenly turn 90 degrees. However, when I draw a stress cube I fail to see...
  4. DerbyEngineer

    Rectangular bar in torsion - why are the shear stresses at the corners zero?

    Thanks again. Not sure why my attachment didn't work last time. Hopefully it will now.http://files.engineering.com/getfile.aspx?folder=f7df55b6-bbb1-4d0e-9eaf-91e8dffe226d&file=Corner_Shear.pdf
  5. DerbyEngineer

    Rectangular bar in torsion - why are the shear stresses at the corners zero?

    Thanks everyone, I think I'm almost getting it. Although not quite... Dhengr - from your attachment: "The material in protruding corners has no shear stress: it is dead material. (This conclusion can be immediately verified by assuming a shear stress in the corner, by resolving that shear...
  6. DerbyEngineer

    Rectangular bar in torsion - why are the shear stresses at the corners zero?

    rb1957 - if my understanding of the "soap bubble" analogy is correct, it is the GRADIENT of the bubble that represents shear stress. Therefore, for a circular section, maximum shear stress (i.e. maximum slope) is at the outer surface and zero shear stress (i.e. zero gradient) is at the centre...
  7. DerbyEngineer

    Rectangular bar in torsion - why are the shear stresses at the corners zero?

    Thanks for your responses, although I'm still struggling. Not sure if my first thread was very clear. The attachment should clear up what I'm talking about.http://files.engineering.com/getfile.aspx?folder=8984779b-f878-4d98-a2c1-4e8261c2f89e&file=Non-Circular_Torsion.pptx
  8. DerbyEngineer

    Rectangular bar in torsion - why are the shear stresses at the corners zero?

    Hi, I'm trying to brush up on torsion of non-circular sections. Taking a bar of rectangular cross-section as a simple example, my textbooks and various websites all say that the shear stress on the outer fibres peak at the mid-points, and are ZERO at the corners. What I don't understand is WHY...
  9. DerbyEngineer

    Seemingly simple free body diagram problem

    Hi all, hope you can help. When drawing Free Body Diagrams (FBDs) is it necessary to consider the stiffness of elements within the structure? I never thought so, until I thought about a simple pin-jointed structure with two truss elements (see attachment). Before considering the relative...

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