Back again, just to confirm im on the right track.
My imaginary defect is 1.5mm in height and 6mm in length, so its a 0.25 ratio?
a (depth of defect) = t x 0.055 = 1.375mm
l (length of defect)= a(1.375) x 4 = 5.5mm
Thus anything over these is a rejectable defect so my 1.5mm x 6mm is...
Thanks for you help.
Just so i can fully get my head around this, is there any chance you can write down the equations needed so i can figure out what would be acceptable/rejectable for the dimensions of pipe i have given. (12 inch x 25mm)
Im a fractions kind of guy and maybe its the decimals...
OK im new to this and im wondering if someone could explain to me in the most basic laymans terms the following ASME acceptance criteria.
If i was looking for what is a defect in 25mm thick pipe that is 12 inch.
ASME B31.12 Table 2 Flaw acceptance criteria
25mm ≤ t 64mm
Aspect Ratio - Surface...