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I see it now... Thanks VTer and Wacross!

TYPO Sorry... Let's say we have only 2 single phase 480V 200kVA transformers connected via A-B and C-A... but no load connected across B-C. That means there is only a total of 400kVA on the upstream transformer. However, if we calculate the current based on Iphase = IAB + IAC, we still get 722A...

Here is a follow up question..... Let's say we have only 2 single phase 480V 200kVA transformers connected via A-B and C-A... but no load connected across B-C. That means there is only a total of 400kVA on the upstream transformer. However, if we calculate the current based on Iphase = IAB +...

Very helpful! Thank you everyone!

Hi folks, I have a 3-phase (3 pole wye connected) 480V circuit breaker that I need to supply three 200kVA single phase 480V identical loads (A-B, C-A, B-C). Only two legs are used for load. As we know, in a balanced 3 phase system, the current across all three phases is kVA / 480V / sqrt(3)...