Thank you guys for the help!
Btrueblood, please help me understand which formula you use.
T=Kdf
T (Nm)
K=0.2
d (m)
f (N)
T= 0.2 * 0.012 * 980 = 2.352 Nm
Why do you double it?
Edit:(Ok, you mentioned 180 degrees angle
So if I will apply force on my torque wrench on 90 degrees angle, I will...
Can anyone help me on the following calculations?
I have a belt & pulley system and a mechanism to create tension (please see attached picture).
I know from the manufacturer how much tension I should apply on the belt (that's ~100Kg = 220lb).
The tension is increased by tightening the nut No1...
