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  1. T53mechanic

    I need clarification on a hydraulic cylinder applied force issue.

    Ok, I went and talked to my boss and we did agree that the amount of force was not enough. I did more digging around and found that the actual piston size is 0.888. I only had the information I could get with calipers. So upon using the formula for force (P*A=F) I found that 2700psi is needed...
  2. T53mechanic

    I need clarification on a hydraulic cylinder applied force issue.

    Thank you for clarifying LittleInch. I know that Ted (hydtools) gave the math, but in your explanation, does the 0.086 dia pin that is transferring the power from the piston matter in the equation? That has been the conflict in this whole thing it seems.
  3. T53mechanic

    I need clarification on a hydraulic cylinder applied force issue.

    Thank you Ted, that was one of the answers I came up with as well. I was afraid we were applying too little pressure to properly seat the pins. IRstuff, Yes it is allowable, the blades are much harder than the pin. As I stated before, the blades go through a florescent penetrant inspection...
  4. T53mechanic

    I need clarification on a hydraulic cylinder applied force issue.

    The blade is driven out with a hammer and brass punch at the root to sheer the pin. Then the machine that presses in the pin, also presses the remainder of the pin out after the blade is removed. Everything gets NDI after the parts are disassembled.
  5. T53mechanic

    I need clarification on a hydraulic cylinder applied force issue.

    What brought this issue about is the manual gives instructions for a different type of machine. It uses air pressure to drive hydraulic pressure to deliver the 2375 to 2425 pounds of force. I will post the whole section of the manual, however please keep in mind that I have not seen this machine...
  6. T53mechanic

    I need clarification on a hydraulic cylinder applied force issue.

    Our manual states the following: "provide 2375 to 2425 pounds of force for driving the blade retaining pin."
  7. T53mechanic

    I need clarification on a hydraulic cylinder applied force issue.

    I hope this clarifies what I am trying to figure out. https://postimg.cc/gallery/1eoq6dqm0/
  8. T53mechanic

    I need clarification on a hydraulic cylinder applied force issue.

    Ok, so if you wouldn't mind confirming for me, 2300psi * (π*0.043)2=13.363 lb/F? So the diameter of the piston does not matter in the equation?
  9. T53mechanic

    I need clarification on a hydraulic cylinder applied force issue.

    Hello everyone. I am currently studying to become an Aerospace engineer. Due to school, I ran into a dilemma at my job. I am afraid it may be a safety of flight issue. I did propose this question to my class, but before I go to our CEO about this issue, I need to confirm my assumptions are...

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