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  1. BuonGiorno

    Hydraulic Jack Spacer or Extension

    I have a hydraulic jack with an 8 inch diameter piston. This means the surface area of piston head is about 50.25 sq. Inches. If I apply 10,000 psi with a hydraulic pump then the force that this jack can lift is about 251.2 Tons. F= P*A 251.2 = 10,000 psi * 50.25 I understand that this holds...
  2. BuonGiorno

    Impact Force of a JackHammer

    What is the best way to calculate Impact Force per Blow given a jackhammer's weight, BPM (Blows per Minute), and Stroke Length? For ,example Ingersoll Rand JH40C3 has a Stroke Length of 67mm, BPM of 2000, and a weight of 27.7 kg. I was thinking to use F=(0.5MV^2)/2 or F=(MV)/T ,but I am...

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