Ted,
I realize that there will initially be some side-force acting on the (red) actuating follower (along the Y-Axis, in latest image). Once the (purple) work-piece rotates in-contact with the 2x (green) cam-followers - until the flat on the work-piece contacts the cyan hard-stop - the line of...
Attached is an isometric-type view of the components:https://files.engineering.com/getfile.aspx?folder=deea999a-a2d6-40b4-8484-1e988132e008&file=FBD_simplified3d.jpg
Ted,
The views in the images are from above the work-piece. Gravity holds the work-piece in the fixture. A vector parallel to the center of either cam-follower is the Z-Axis (assuming the X-Y plane is parallel to the floor.
Although, in the images, it appears that the work-piece is a cam it is...
Thanks folks. My initial post was not as clear as it could have been. I realize that the layout shown in the "Initial" image is a dynamic and not a static situation (and that the work-piece should rotate in a CW direction until it contacts the fixed stop).
I believe that the layout shown in the...
Thanks 3DDave,
I wanted to be sure that the part will move until it contacts the stop.
What I am also unsure of is whether there will be some forces (of undetermined magnitude) as shown by the force directions shown in the "Final" diagram - such that there are reaction forces holding the...
Greetings,
It has been a long time since I used FBDs in school.
I do remember that for the system to be in static equilibrium (in XY plane) that:
The sum of the forces must equal zero
Sum of forces in X must equal zero
Sum of forces in Y must equal zero
The sum of the moments (about a...
