Hi dvd,
Thanks for your reply.
Just to check, you say it's a vector sum, so:
Fp = T (1 + sina)
Fq = T (sinb - cosa)
Leading up to
Fp = Fq (1 + sina) / (sinb - cosa)
Is this what you mean?
Take R as the driver rotating clockwise. That means T1 > T2 (new diagram).
From my studies, T1 and...
In this conveyor belt configuration, rollers P and R are horizontally aligned, while rollers R and S are vertically aligned, in a triangular arrangement. Roller Q then bends the belt between P and S.
Roller Q is free to slide vertically, while roller P slides horizontally. The remaining rollers...
Hi desertfox,
That was a typo. I did divide by the radius to obtain tangential forces.
To dvd and other readers,
I've attached a diagram. However, the inclination is not indicated as I have no information on that; in my approach, this was not required (please correct me if I am wrong)...
Hi everyone,
I would like some validation on my calculations of the required torque and power for a motor to drive a heavy but slow conveyor belt assembly. I feel that I may have underestimated these values significantly.
Method of driving: Motor pinion drives a large roller via a internal...
