georgeverghese:
The turndown ratio on the heater is 10:1.
If we are controlling flow in the return, and if one or more valves close, flow will go the the next system, making the return flow the same and the supply, that will increase the dp across each tank, will it not?
georgeverghese:
There are a couple of question regarding your sketch:
1. Why 6" sub-headers and not 4"? I know you are trying to keep a similar dP per unit length, but using a 6" will increase the cost, and dp on a 4" line is not that terrible.
2. Why is a backpressure control less preferred...
Compositepro:
You hit it right on the head, that's the main reason we cannot use an electric heater, the liquid being heated is too sensitive, we have used electric heaters in the past and it will burn the product.
Certainly, not all tanks have this issue and we could have a combination of...
I want to thank all of you for helping me with this.
LittleInch:
Each production line has 14 tanks, so yes, we are going to have 56 tanks that will need to be heated.
Each tank will have its own temperature transmitter and controller to adjust the flow going inside each coil.
I was planning...
Thank you all for taking the time to answer.
I will answer everyone on this post.
@Jari001:
I have done a quick P&ID
It doesn't have lengths or all the components but I hope that makes it clearer.
The image shows 4 systems (production lines)
These are the total pipe lengths:
1" pipe...
Hello everyone,
I'm currently designing a thermal oil system.
I have sized up the heater (16MBTU/hr) with 1,200 GPM flow rate.
I'm having issues calculating the pressure loss (due to friction) in my piping system. I'm confused when it comes to how to calculate this.
I know I have to add...
JStephen,
I understand the compressive ring now based on your response, that makes sense.
Now, if I look immediately below the cone junction, you said that I only have the weight of the liquid in the cone + the weight of the cone shell and they go in the same direction as pressure.
Based on...
LittleInch,
I think you are talking about API 650, that one works with flat bottomed cylindrical tanks.
API 620 comes into play when you have cone tops or bottoms.
With the tank sizes I'm working on, if I had a flat bottomed tank, I think I would use AWWA D-100, because I'm dealing with...
@JStephen
Thank you for taking the time to view my post and answer me.
I was struggling with the fact that we are subtracting a pressure value (when you are considering the cylinder), understanding that there is no negative pressure (unless you have a vacuum).
I'm also having a difficult...
Hello everyone.
Im designing a couple of tanks with a cone bottom, I'm using API 620 for this. Im not sure If I got my numbers right. Can you help me?
This is the information for the tank
Wshell = 3345 lb
Wimpeller = 486 lb
Wliqshell = 52,712 lb
Wtop = 638 lb
Wcone = 445 lb
P at 20ft =...
JStephen,
I did the analysis for the shell, and I did get a low T1 = -25.63 Lb/in, T2 at that point was 1,068 lb/in.
T2 = P*Rc - 14.84 x 72
You are right on the cone, I was doing my FBD wrong, T1 and T2 are Positive.
T1 = 309.16 lb/in
T2 = 12,888 lb/in
Since both are positive, I use the...
Hi,
Im new working with API620 and need some guidance.
Im designing several storage vertical cylindrical tanks base on API 620.
One of the tanks has the following data:
Radius = 72 in
Shell Height = 34ft.
Wshell = 12,500 lbs.
Wroof = 831 lbs.
Density = 62.4lbs.ft3
Cone bottom.
Cone Radius =...
Geoff13
You are right, I misunderstood your term "corroded thickness" with corrosion allowance.
Using that eq. I get Scc = 18.34/0.1875... Scc = 98 PSI and Stc = 56 PSI.
Like you were saying, since my tank is very small and pressures are low.
Taking that Scc and doing an analysis with t =...
Geoff13
Where did you get that formula for Scc and Stc?
If you do that shouldn't the formula be Scc = T1/(t-c) and Stc = T2/(t-c)? why is the pressure only acting against the corroded thickness and not the thickness of the shell minus the corroded thickness?
JStephen
This is what the standard says "in cases where the unit force acting in compression does not exceed 5% of the coexistent tensile unit force acting perpendicular to it, the designer has the option of permitting a tensile stress of the magnitude specified in 5.5.3.2 instead of complying...
Im new working with API620 and need some guidance.
Im designing several storage and mixing vertical cylindrical tanks base on API 620.
One of the tanks has the following data:
Radius = 40 in
Wshell = 3800 lbs.
Wroof = 550 lbs.
Wimpeller = 300 lbs.
Density = 998 kg/m3
Cone bottom.
Opened to...