Rb1957 is right, don't waste any more time, as such a complex and difficult-to-understand analysis, will not be necessary for this work wich is a simple school projet, but it was already possible anyway for learning how structures work and other solutions such as the Moment Area method and the...
BA do you agree with this ? In the horizontal defletion SD=SC=155P*200^2/2E1 why is E1 It shouldn't be E2?
In the vertical defletion the term PL^3/3E1=5*310^3/(3*130.4e6) could you explain?
Rb1957 it is a simple 3D part on solidworks.
Thanks
I understand butt the linear straing gauge is on the x axis position. So responds to bending moment butt analiticaly is zero.
Mfx=265*P
Analiticaly Sigma x= (Mfx*y)/I=(265*P*y)/I)=0
The Experimental value that obtained for 5 [N] of -0.229 MPa and deformation of -3.330 us shows that is reading...
BA I was checking your calculations, however I still have some doubts about how you arrived at some equations. Can you check if the sketch I made corresponds to the displacements and slopes?
Why thetaC is the sum of thetaB and the change of slope between BC? Shouldn't be only the change of...
BAretired could you explain how do get 232.5 value on tetaC.
You can make a sketch of what each calculation refers to as I did in the diagram. It's hard for me to understand.
I experimentally obtained from the dial indicator a displacement for a load of 5 N of 1.491 mm and for 7 N of 1.931 mm...
BAretired its aluminium alloy 6063-T6 E=69GPa
For tube AB and CD: (Do=15,6 Di=12 mm)
i'm calculating I=pi*(15.6^4-12^4)/64=1889,26 mm^4
So EI=69e9 (Pa)* 1889,26e-12 (m^4)=130.36 N.m^2
For tube BC:
I=(20x10^3-17x7^3)/12=1180,75 mm^4 (the tube its 20x10x1,5 mm)
So...
OK. rb1957 I had calculated again. i'm not considering the displacement due to shear, do you think it is significant?
Should i use Deltax=(Tau * L)/ (G *A) ?
On the AB tube:
I was using x (0 to 310 mm) on first post. But i think its (0 to 150 mm ) on AB tube. it is right?
Now for a P=5 N i...
Hello again.
I am calculating the displacement using the Castiglian theorem as in the annex, but I am obtaining analytically for example for P=5N, a displacement of SD=0.7 mm on D position.
(0.140136x5=0.7 mm)
When experimentally, on the comparator, It obtained a value of displacement of 1.4...
ok. rb1957 you say that at the rosette section, transverse stress is zero, then shear stress is zero because is hollow the vertical (retangular) tube ?
in mohr circle for rosette , then i consider tau_xy=zero right?
But in the horizontal circular tube i where i have the linear gauge section...
Ok i get it, the rosette reads the deformation on the axis of vertical tube, so the arm is 155mm . Ok I think youre right.
I had an error. Area of the vertical tube is A=20x10-[(20-2x1,5)x(10-2x1,5)]=20x10-17x7=81mm2 the area is 81 mm2
rb1957 do you know how do i make calculation of...
Hello.
Yes P is applied parallel to the vertical tube, there's no torque.
So the for the strain gauge 0-45-90 or rosette on the cross section the total stress is:
Sigmax= -P/A - (Mfy*y)/I = - P/81 -(155*P*(10/2))/(1180.75) [MPa][/b] rb1957 I didn't understand why 155 mm? The rosette is on...
Hello, I need some help about this project. I need to calculate the internal forces and moment, normal stress and shear stress in the 0-45-90 strain gauge and for the linear strain gauge. However, I have doubts, especially how to calculating the shear stress and whether the internal forces are...
