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Yea so my understanding is, we need to know the absorbed power or the shaft power whichever we are going to call or name it. So it should be lower than the kW that we are paying for. We need to find out what is the real power after the losses at the motor shaft after motor efficiency and VFDS...

"If you mean power FROM the electric motor into the driven equipment (aka shaft power) then multiply by efficiency." This statement is correct to me then, so it multiply be efficiency ! thanks tons !!! [cheers]

Let me try rephrasing, i will like to know the power consumed at the motor shaft, therefore i guess it call shaft power ?

Greetings fellow seniors, I am a new mechanical guy who just got into the line in a utility plant and I am a lost one with electrical stuff, so I was wondering I can get some insight and understanding from the brains. So part of my job was to get the real input(absorbed)motor kW reading from...