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OK pulled the book out and I think we're both right - kinda: You've modeled the wheel as a thin shell therfore I=mr^2 I modeled it as a thin disc with so ariving at I=mr^2/2 Where what may be more appropriate but overcomplicating things for the purpose of proving (or disproving as the case may...

Please disregard last comment.

Sorry typo * between I and W terms should be + sk

Think we're disagreeing on value for Inertia of a wheel, from memory I though mass moment of inertia of a solid disc about it's origin was m*r^2/2, memory could be failing ;-)have to check that...? Rgds Sean

I didn't quite follow as to how the figure of 2:1 was arrived at so had a go at the Energy method and came up with a slightly different result: The change in kinetic energy of the system due to a change in wheel mass "m" at radius "r" on a wheel with a radius of...