Search results for query: *

Ah, I forgot: v = especific volume Regards. Luiz

TBP wrote: > What are you trying to calculate? Darcy equation hf = f*(LV^2)/(2gD) and Colebrook equation f = 0.25*[-log(0.27*k/D + 2.51/(Re*f^0.5))]^-2 (with SI units) Sarco equation: J = 3650.88 * Q^1.95 * v^0.95 * D^-5.1 (with: [D]=mm, [v]=m3/Kg, [Q]=Kg/h and [J]=Kgf/cm2 per 100m)...

jproj wrote: > Your units conversion is not correct... Yes. I'm sorry. But, forget the english units. It is not correct, but the SI units is correct. Then by the Colebrook/Darcy formula, we have: hf=4,442.73 m but, by the Spirax Sarco formula: hf=26.4 m Why this huge difference? Is anything...

For satured steam in steel pipe under 8 Kgf/cm2 (113.7 psi) and D=0.10226 m (4" schedule 40) k=0.0001m (0.0000305 ft) V=30 m/s (9.14 ft/s) v=0.0000035 m2/s (0.0000011 ft2/s) L=500 m (152.4 ft), by Colebrook and Darcy formulas, we have: hf=4,442.73 m (1,354.14 ft) But, by Spirax Sarco...

Ok Morel. For satured steam in steel pipe under 8 Kgf/cm2 (113.7 psi) and D=0.10226 m (4" schedule 40) k=0.0001m (0.0000305 ft) V=30 m/s (9.14 ft/s) v=0.0000035 m2/s (0.0000011 ft2/s) L=500 m (152.4 ft), by Colebrook and Darcy formulas, we have: hf=4,442.73 m...

Hi MorelG My fluid is satured steam flowing in pipes, say, at 35 m/s under 120 psi. So Ma = 35/340 = 0.1 Is it considered incompressible? Thanks

Hello dazma, Can you tell me how to get the Mach number? Thanks. Luiz

GGW: This is the question: I would like to use Darcy and Colebrook equations to compute satured steam flow pipes size, say, 120 psi. Can you tell me what is this equation of state? Thanks. Luiz

Does anyone know where I can get a steam bulk modulus table? Tanks a lot. Luiz

For pipe design flowing incompressible fluid, I use: Darcy equation hf = f*(LV^2)/(2gD) and Colebrook equation f = 0.25*[-log(0.27*k/D + 2.51/(Re*f^0.5))]^-2 where: hf = friction loss f = friction factor L = length V = velocity g = gravity D = diameter k = equivalent roughness Re =...

For pipe design flowing incompressible fluid, I use: Darcy equation hf = f*(LV^2)/(2gD) and Colebrook equation f = 0.25*[-log(0.27*k/D + 2.51/(Re*f^0.5))]^-2 where: hf = friction loss f = friction factor L = length V = velocity g = gravity D = diameter k = equivalent roughness Re =...

I'm looking works, papers or article about waterhammer or hydraulic transients. Is there anyone who knows where I can get it? Thanks. Luiz

I'm looking works, papers or article about waterhammer or hydraulic transients. Is there anyone who knows where I can get it? Thanks. Luiz