I figured it out. You can use fnval in the manner which I said could not be done.
ie..
m(1:n) = fnval(t(1:n),f1) + fnval(t(1:n),f2)
not sure what I was doing wrong before, but this does work, and my time to compute on cycle went from 2.4sec to .35sec.
Regards,
jason m.
"Education is what...