I forgot to mention something very important. The voltage cannot drop below 3.1V. With a series resistor that limits the current to about 500 mA the Vdrop will be about .7V which will drop the supply voltage from 3.6 to 2.9, which will not allow the circuit(load) to run.
I'm working on a pulse power design. The duty cycle is 10%: .1sec ON @ 100mA, 1sec OFF(sleep) @ 0.1mA. The super cap (.47F) will be discharged at startup. What is the best way to combat 'inrush' at startup? My goal in this design is to power the circuit with a 3.6V battery and when the...
