I've got other equations;
My main issue is substituting in the L. That was my question.
Can I set x=L and have it evaluate the function in terms of L.
Whenever I set x=L it just complains that L isn't defined. Well, I don't wanna define it.
I'm trying to solve a problem purley symbolically, my boundary conditions for my equation is 0 and L.
quick example:
My equation is
v(x,c0,c1,c2,c3):= c0+c1*x+c2*x^2+c3*x^3
x:=0
v(x,c0,c1,c2,c3)-> c0
that works fine
my problem is I would like to evaluate this at x=L as well.
So I would...
