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  1. PMPPEng

    secondary fault calculations using utility primary fault current

    That is true. It was a mistake. Correct the 15% to 0.15 p.u and carry out the calculations.
  2. PMPPEng

    secondary fault calculations using utility primary fault current

    Here is an example: 1 Primary Bus Voltage 132 kV 2 Fault current at Primary Bus 15 kA 3 Fault MVA 3429.36 MVA 4 Transformer Ratio 132/25 kV 5 Transformer imp (on its rating) 15 % 6 Transformer rating 100 MVA 7 Choose a base MVA 100 MVA 8 Fault imp based on base MVA 0.02915996 p.u...

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