I agree it appears that I am off by a factor of 100, but I am not sure why.
The equation I am using is:
Square root of (360degrees*Holding Torque)/(step angle*Inertia)
I am trying to calculate the natural frequency of a stepper motor.
Here is my work so far.
The motor is rotated .3 degrees with a torque of .32 N*cm.
Inertia = 48 g*cm^2
200 step/rev
1.8 degrees per step
I am using the equation frequency = sqroot of (200*.32)/48
Which = 1.1547 steps/sec...