Does anyone know a code or a mechanical requirement/justification to have two or more threads pass the nut when torquing hex nuts. I have been told that at lease two threads must show pass the nut and I am not sure why. Please respond. Thanks
You should simply use the following formula:
FT=MV good luck. F+ Force T= Time M=Mass V=Velocity
You can calculate all of above using simple math and then obtain Force. Good luck!