Thank you MikiBG, i confused stator copper losses, when i calculate Pfe i must take Io in stator copper losses, but when i calculate total stator cooper losses In must be taken.
I have found one my mistake by calculating stator copper losses, Io is no-load current and i must take In (nominal current)as you say.
Ressistance is per phase, no problem here.
Iron losses (Pfe) =Po(no-load input power)-Pcu(172,8w)-Pwf(friction and windage)
Pfe=209-172,8-28
Pfe=8,2W (is it...
Thank you edison123,
power factor is at no load is 0,12 (400v) and locked rotor pf= 0,62 (68v) i think they are not very small. ohmmeter is already micro ohmmeter i didnt write down here 0,001 . But Pk is high you are right. I test locked rotor at 50Hz does it affect the Pk?
Thank you ScottUK
So you mean that Stator losses in that formula shuold be included windage (friction+wind), and rotor iron losses ,
but those losses all about rotor? in this formula i need to find stator losses (stator iron + stator copper ) Am i wrong?
Dear Sirs
I have some question about to determine losses of a small three-phase induction motors with sqiruell cage rotor. Motor is 2kw - 2 poles, nominal current is 4.8A, Y connection, 400V/50 Hz.
I locked the rotor and voltage is zero, than the voltage is increased, till nominal current...