Based on some other information I have come across:
If the value is opened for a long enough period of time to let the cylinders equalize with the atmosphere then the density in both cylinders will be the same. But if the valve is opened only for a short time then the rate at which air flows...
Just so that I am clear.
You do feel that there will be an independent temperature and/or pressure effect. And you feel that the cf equation, altough it may not be calcualting the horsepower exactly, it is correct that it is showing an increase in power when the temperature and pressure are...
This was exactly my concern. I really can't reason why this should happen. I would think if the cylinder has the same amount of O2 it could make the same power.
So do you feel it is plausible that you may make the same power with the same density eventhough one air sample comprises a higher...
Irstuff -> Is this better? The difference in the temperature of the charge, even though at the same density, can effect the combustion process additionally to create power.
Do you feel this effect is independent of pressure?
Might it be reasoanble that if we had a similar scenario with more...
Sure there are many factor to make horsepower. But the atmoshere in which we are discussing has exactly the same amount of oxygen in it. So unless I can figure out how atmosphere B causes more oxygen to fill in the cylinder I cannot understand why it woudl create more power or from where that...
I posted the question on the thermodynamics forum because I did not feel it was really an automotive based question. I have still yet to confirm this so I am posting here geared more towards an automotive question. I am not trying to cross post so I hope the moderator understands, just looking...
Here is why I asked the question to begin with. For internal combustion engines they use a dyno correction factor (cf) to correct for horsepower in different atmopheres.
IF you calculate the cf using the values shown above the cf will be less(more power) for the atmophere with the higher...
What is looks like to me, at this point, is that either when the valves are open each cylinder will end up with the same number of molecules based on PV=nRT or Zekeman is on the right path with looking at the problem based on the amount of Work=PV.
Any further insight on this would be appreciated.
If I use
https://www.brisbanehotairballooning.com.au/faqs/education/116-calculate-air-density.html
to calculate teh air density of both atmopheres
Cyl A:
70F -> 294.26111K
29inHg -> 98205.2565PA
Cyl B:
80F -> 299.816666K
29.5475-> 100059.304Pa
I get the same density 1.163kg.m^3 for each...
I thought about this some more last night and got confused again because I didn't understand how i could have a different number of moles if the density was the same?
Zekeman comments may be more relevant to this problem.
So I assume now i have to base it on a new T that is created after the...
Cyl A:
70F -> 294.26111K
29inHg -> 98205.2565PA
Density 1.16272
Volume=2.99638e-3 x R
Cyl B:
80F -> 299.816666K
29.5475-> 100059.304Pa
Density 1.162721
Volume=2.99638e-3 x R
Based on these calc's the volume of air in each cyl is the same....
I was told that the air with the...
PV=nRT Ideal gas law
Can you please explain in more detail how to apply the ideal gas law to this example?
Don't both atmosphere weigh the same per volume and doesn't that weight cause the atmosphere to fill the cylinders?
I am trying to understand what would happen in a certain scenario regarding an internal combustion engine. I am trying to determine why might a cylinder fill with more atmosphere when comparing two atmosphere's that have the same density, but one has higher pressure.
Lets say we have two...