Hello, I have a general question regarding 2 different pumps in series.
In this situation the head is added and flow remains the same Q = Q pump1 = Q pump2.
Also I read if the capacities of the pumps are different the flow is determided by the smallest pump.
But in practical situation , what about if the 1st pump is delivering less water than the 2nd pump? I found that the 2nd pump will suffer and cavitation will occur, I am right?
Is there a guideline how big this difference must be to get this problem? Or how to calculate it?
Can this be prevented by simply reducing the power of the second pump by the frequency driver to match the flow rate?
Thank you!
In this situation the head is added and flow remains the same Q = Q pump1 = Q pump2.
Also I read if the capacities of the pumps are different the flow is determided by the smallest pump.
But in practical situation , what about if the 1st pump is delivering less water than the 2nd pump? I found that the 2nd pump will suffer and cavitation will occur, I am right?
Is there a guideline how big this difference must be to get this problem? Or how to calculate it?
Can this be prevented by simply reducing the power of the second pump by the frequency driver to match the flow rate?
Thank you!