Sn00ze
Electrical
- Jan 16, 2013
- 176
I am questioning my coworker and he hasn't been able to give me a satisfactory answer either.
So, i am hoping to get an answer from here in hopes to understand it better and explain it or have it explained to me.
We have a system being fed from a station service TX. 120/208V 3-ph to our AC panel.
We are feeding a circuit breaker from this panel with 240V heaters so they had to install an aux Tx to step the voltage up from 208V (phases A and B).
So, up to the TX the load is 5.4kVA. but the transformer is 208V to 240V. So what is the current in each of the legs coming from the AC panel?
is it simply kVA/208V ? Iin=Iout?
or do we need to kVA/208V*1.73.
thanks
So, i am hoping to get an answer from here in hopes to understand it better and explain it or have it explained to me.
We have a system being fed from a station service TX. 120/208V 3-ph to our AC panel.
We are feeding a circuit breaker from this panel with 240V heaters so they had to install an aux Tx to step the voltage up from 208V (phases A and B).
So, up to the TX the load is 5.4kVA. but the transformer is 208V to 240V. So what is the current in each of the legs coming from the AC panel?
is it simply kVA/208V ? Iin=Iout?
or do we need to kVA/208V*1.73.
thanks