bdn2004
Electrical
- Jan 27, 2007
- 794
The Utility sent us the available short circuit for the Plant – appx 13 kA at 12.47 kV. X/R = 19
Since then, I actually looked at the nameplate on the Utility transformer. It has these ratings: 15/20/25 MVA ONAN/ONAF/ONAF. 13800-13090/7558 V and 9.10% impedance at that voltage and 15MVA.
I tried to model in our software this transformer and produce on the secondary side the same short circuit value the Utility had provided. But no matter how much primary short circuit MVA is available – the 15 MVA transformer will never produce 13kA and will produce like 7.5kA. The infinite bus method answer which makes some sense.
If I use 25 MVA as the maximum transformer size – it does give a much closer number as what they had sent us from the Utility. Is that the answer – you must use the maximum size listed on the nameplate? If that’s the case why don’t they give you the impedance at that maximum value on the nameplate and just call this a 25 MVA transformer?
Since then, I actually looked at the nameplate on the Utility transformer. It has these ratings: 15/20/25 MVA ONAN/ONAF/ONAF. 13800-13090/7558 V and 9.10% impedance at that voltage and 15MVA.
I tried to model in our software this transformer and produce on the secondary side the same short circuit value the Utility had provided. But no matter how much primary short circuit MVA is available – the 15 MVA transformer will never produce 13kA and will produce like 7.5kA. The infinite bus method answer which makes some sense.
If I use 25 MVA as the maximum transformer size – it does give a much closer number as what they had sent us from the Utility. Is that the answer – you must use the maximum size listed on the nameplate? If that’s the case why don’t they give you the impedance at that maximum value on the nameplate and just call this a 25 MVA transformer?