joedunai
Mechanical
- Mar 3, 2012
- 18
I am studying the acoustic wave attenuation in thin tubes. One of the classic papers that discuss the subject is “On the propagation of sound waves in cylindrical tubes” by H. Tijdeman. It contains all the formulas and tables needed to calculate the attenuation in thin tubes filled with air. Since this is an advanced text, it does not dwell on the in-depth description of the physical mechanism besides noting, that the acoustic power is getting dissipated in the viscous boundary layers, and by heat conduction.
My problem is in understanding the difference between power dissipation of an acoustic wave vs. power dissipation of a simple fluid flow (laminar or turbulent) in the same tube & medium. When I calculate the attenuation (power loss) of a wave, it is much higher than the power dissipated by a simple fluid flow within the same tube having the same velocity as the fluid molecules in the wave. This is especially noticeable when the medium is not gas but liquid, and the molecule velocities are very small.
If both acoustic and simple flows encounter the same viscous and heat conduction losses in the boundary layers, then why is there a big difference between the power losses?
There is an analogy between fluid dynamics and electricity. In electrical engineering the thin tube is analogous to a resistor. The resistor dissipates the same power as long as the applied effective voltage is the same, be it direct current (like simple steady fluid flow), alternating current (alternating fluid flow), or conducted EM waves (analogous to acoustic waves). If the analogy stands in this regard, shouldn’t the thin tube behave in a similar way?
Any input on this subject is appreciated.
Joe
My problem is in understanding the difference between power dissipation of an acoustic wave vs. power dissipation of a simple fluid flow (laminar or turbulent) in the same tube & medium. When I calculate the attenuation (power loss) of a wave, it is much higher than the power dissipated by a simple fluid flow within the same tube having the same velocity as the fluid molecules in the wave. This is especially noticeable when the medium is not gas but liquid, and the molecule velocities are very small.
If both acoustic and simple flows encounter the same viscous and heat conduction losses in the boundary layers, then why is there a big difference between the power losses?
There is an analogy between fluid dynamics and electricity. In electrical engineering the thin tube is analogous to a resistor. The resistor dissipates the same power as long as the applied effective voltage is the same, be it direct current (like simple steady fluid flow), alternating current (alternating fluid flow), or conducted EM waves (analogous to acoustic waves). If the analogy stands in this regard, shouldn’t the thin tube behave in a similar way?
Any input on this subject is appreciated.
Joe