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Adiabatic action

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aquafied

Mechanical
Jan 16, 2013
18

In an adiabatic situation is the heat required to liberate all the ammonia vapour from a given mass of water, exactly the same as the energy gain when the same mass of vapour is re-absorbed, in other words is more energy needed to brake the bondage?
 
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It is exactly the same. E[sub]break bond[/sub] = E[sub]make bond[/sub].

Good luck,
Latexman

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A reversible process is isentropic, I believe. Adiabatic simply means that no heat was lost from your "system". That does not make it thermodynamically reversible.
 
Relying on the second law of thermo, this process is not reversible because entropy increases.
 
Aquafied
While charging Ammonia into water the mixture becomes extremely hot, indicating a chemical action is occurring. To liberate this quantity of Ammonia from the mixture heat is required so if no heat is gained or lost (externally) during the absorption or liberation process is the energy exchange even?

I can cope with enthalpy but not entropy.

 
It will not be exactly equal, but close enough for your purposes.
 
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