eeprom
Electrical
- May 16, 2007
- 482
Hello,
I received some German wiring for a shop crane. For the trolley, there are two speeds used, no VFD. So the speed control must be done by adding or removing poles. I am stumped as to how the speed control works.
The wiring has 6 leads to the motor, labeled 1, 2, 3, 4, 5, 6. These wires are shown on the dwg as 2 parallel sets of three phase power to the motor.
The wiring at the motor is shown as (from the left) U1, V1, W1, and (from the right) U2, V2, W2.
Wires 1, 2, 3 are phases ABC, and wires 4, 5, 6 are also phases ABC. 1 is jumpered to 3; 2 to 4, and 3 to 6.
Downstream of the jumpers is one 4 pole contactor, making or breaking wires 2, 3, 4 and 5. On wires 2, and 3 there is a NO contact labeled (FAST). On wires 4 and 5 are the NC contacts of the FAST contactor. There are no contacts on wires 1 and 6, so these are always energized (assuming the motor is on).
So when FAST is energized, the wires 1, 2, 3, and 6 are energized, or phases A,B,C, and C are energized, (or U1, V1, W1, and W2 are energized). When FAST is not energized, wires 1, 4, 5, 6 are energized (or U1, U2, V2, W2).
I don't know how many poles the motor is, but let's just assume 4. I have been looking at diagrams ( in the Robert Rosenberg, August Hand book) on how to wire a motor to switch it from 4 poles to 8 poles, thereby cutting the speed in half. But I cannot see how the wiring I have could possibly result in this.
Can someone please explain how the wiring configuration explained here can result in two speeds on a 3 phase motor?
thanks for your help
EE
I received some German wiring for a shop crane. For the trolley, there are two speeds used, no VFD. So the speed control must be done by adding or removing poles. I am stumped as to how the speed control works.
The wiring has 6 leads to the motor, labeled 1, 2, 3, 4, 5, 6. These wires are shown on the dwg as 2 parallel sets of three phase power to the motor.
The wiring at the motor is shown as (from the left) U1, V1, W1, and (from the right) U2, V2, W2.
Wires 1, 2, 3 are phases ABC, and wires 4, 5, 6 are also phases ABC. 1 is jumpered to 3; 2 to 4, and 3 to 6.
Downstream of the jumpers is one 4 pole contactor, making or breaking wires 2, 3, 4 and 5. On wires 2, and 3 there is a NO contact labeled (FAST). On wires 4 and 5 are the NC contacts of the FAST contactor. There are no contacts on wires 1 and 6, so these are always energized (assuming the motor is on).
So when FAST is energized, the wires 1, 2, 3, and 6 are energized, or phases A,B,C, and C are energized, (or U1, V1, W1, and W2 are energized). When FAST is not energized, wires 1, 4, 5, 6 are energized (or U1, U2, V2, W2).
I don't know how many poles the motor is, but let's just assume 4. I have been looking at diagrams ( in the Robert Rosenberg, August Hand book) on how to wire a motor to switch it from 4 poles to 8 poles, thereby cutting the speed in half. But I cannot see how the wiring I have could possibly result in this.
Can someone please explain how the wiring configuration explained here can result in two speeds on a 3 phase motor?
thanks for your help
EE