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Air compressor room air changes

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checonbill

Electrical
Mar 17, 2006
22
Could someone let me know what would be a reasonable air change for a small compressor room 15 x 15 x 12 with a 150 hp compressor I need to drop the temperature in the room it is apx 140 degrees when the outside temp is 90.
 
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checonbill (Electrical)
I have a similar compressor room. 10x20x12. I am removing 1500cfm which gives me 2 air changes per min.
Even that is marginal on a hot day with the sun beating on the compressor room.
I am presuming that your compressor is venting it's heat into the room.
B.E.
 
As per ASHRAE Handbook of Fundamentals, for a motor driven machine, both in the conditioned space,
heat gain = (Hp/Eff.)*load factor*2545 = BTUH

Load factor is the fraction of the load delivered (how much does it run?).

Assuming 80% efficiency and 50% load factor (runs half the time),
BTUH = (150/.8)*.5*2545 = 238594 BTUH.

Assuming room is to be kept at 95,
CFM = 238594/((95-90)*1.08) = 44184 CFM. I would use a roof mounted axial fan. They move lots of air at low static pressure.

Of course, this neglects solar heat gain. As the ventilated room temperature approaches ambient air temp, the cfm required goes to infinity. The only way to get it to ambient (without refrigeration) is to remove the roof.

Hope this helps.
 
Our numbers are a little off, but I agree with trashcanman's calcualtions. I usually figure a laod factor of 1, so my numbers are double for the same delta-T. It seems liek every industrial compressor room I have ever been in have all units running full-bore.

In lieu of specific manufacturer data, here is what I have used.

1 HP = 746 Watts
Assumme 80% efficiency, so each compressor HP = 933 Watts

Add 1/10 HP per compressor HP for dryers or 93 Watts

This totals 1,026 Watts per compressor HP or roughly 3,500 BTUH per compressor HP.

(CFM/HP) = (BTUH/HP)/1.08/Delta-T

Your Delta-T is your allowable or desirable room temperature minus the outside air temp. In other words, if you want to keep the room at 105, and your outside air is 95, then your Delta-T is 10.

Using 10 deg Delta-T, your required CFM/HP is 3,500/1.08/10, or 324 cfm/HP

With a 150HP compressor, you will need 48,600 CFM. This is obviously a truckload for such a small room. You may not have enough free wall/roof space for fans and louvers. Direct vent the compressor heat outside if you can. Be careful, however, because most air-cooled compressor fans can handle very little static. Consult with the manufacturer.
 
There may be an error in here somewhere. If a 150 HP motor/compressor has an efficieny of 80%, that means that 80% or 120 hp goes into useful work of compressing the gas. The remaining 20% shows up in heat from the motor windings, bearings, inefficiency, etc. The heat in the room (igonoring solar, vents, conduction, and other sources and sinks) is then 20% of 150 hp or 30 hp which equates to about 1272 btu/min. An airflow of 14,553 ft^3/min is required for a 5 deg temp difference at a load factor of 1. It gives 5.4 air changes per minute.

Regards
Dave
 
Cessna1 is correct, providing the intercooler and storage tank are not colocated with the compressor - usually outside of the building for this reason.
You might consider relaxing the interanl temperature criteria.


 
checonbill (Electrical)
This is why I asked if the compressor was venting it's heat into the room.
Without the heat load of the inter cooler and the dryer, 2 to 3 air changes per min should cover it with capacity to spare, if not then as CESSNA1 says you will need 5 to 6 air changes. The calculation imok2 (Mechanical) did on your related post looks closest if you do not have an inter cooler venting in the room.
 
Cincimace, I hear what you are saying with the intercooler, but why is the location of the storage tank inportant? In theory, shouldn't the leaving compressed air temperature be the same as the entering?
 
BronYrAur (Mechanical)
As the air is compressed into the tank it heats the tank.
If the demand on the system is not constant, that heated air just sits there and heats the room.
B.E.
 
I simply mean; When the comp air storage temp is higher than the ambient, heat will flow from the tank to the space.
 
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