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Amount of component x condensed along with water vapour during reaction

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chemks2012

Chemical
May 15, 2013
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Hello all,

Need your help please.

I want to calculate amount of component x condensed along with water vapour during reaction. The reactor batch is 10 tonne.

The reaction takes place at 180 degC at which component x is removed and condensed.

Vapour pressure of the component x at 180 degC = 0.001
Vapour pressure of water at 180 degC = 10 bar

Molecular wt of component x = 300 g/mol





 
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Using simple rules such as Raoults Law to compute the water condensed would be appropriate only if the reaction mix is ideal - for non ideal mixes, there would be significant deviations.
 
Thanks all,

I don't think Raoult's law would be applicable here.

Please let me know if my calculation below is correct

Here, X is mass % of component x

((X⁄300))/((((100-X))⁄18) )=0.001/10

((X⁄300))/((((100-X))⁄18) )= 0.0001

x/300=(0.0001*(100-X))/18

18X=0.03*(100-X)

18X=3-0.03X

X=1.66%

Thanks
 
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