MoonBridge
Structural
- Nov 26, 2024
- 2
Hi,
I would appreciate some advice regarding how to apply wind loads directly to the substructure of a bridge at angles different than 0° (per AASHTO).
AASHTO states to resolve the load into two component loads each perpendicular to the end and front elevations respectively. My understanding is that the end elevation would refer to the portion of the cap visible from a side elevation view and the front elevation refers to a view equivalent to a view of the substructure as one would see from a transverse section cut.
Assuming this is an accurate interpretation, for a 0° angle of attack, the exposed area of the end elevation would be (bent cap height)*(bent cap width) and then the force would be found by multiplying by the calculated pressure.
The exposed area of the front elevation would be 0 since the wind pressure is being applied perpendicular to the bridge's longitudinal axis.
When the angle != 0, my current approach is to multiply the exposed area of the end elevation by cos(θ) and the front elevation length by sin(θ) to find the adjusted exposed areas. This makes some sense in that when θ is equal to 0 all the load is transferred to the end elevation and as the angle increases, more load is transferred to the front elevation. However, I'm not sure if this is the correct approach.
Any advice would be helpful,
Thanks.
I would appreciate some advice regarding how to apply wind loads directly to the substructure of a bridge at angles different than 0° (per AASHTO).
AASHTO states to resolve the load into two component loads each perpendicular to the end and front elevations respectively. My understanding is that the end elevation would refer to the portion of the cap visible from a side elevation view and the front elevation refers to a view equivalent to a view of the substructure as one would see from a transverse section cut.
Assuming this is an accurate interpretation, for a 0° angle of attack, the exposed area of the end elevation would be (bent cap height)*(bent cap width) and then the force would be found by multiplying by the calculated pressure.
The exposed area of the front elevation would be 0 since the wind pressure is being applied perpendicular to the bridge's longitudinal axis.
When the angle != 0, my current approach is to multiply the exposed area of the end elevation by cos(θ) and the front elevation length by sin(θ) to find the adjusted exposed areas. This makes some sense in that when θ is equal to 0 all the load is transferred to the end elevation and as the angle increases, more load is transferred to the front elevation. However, I'm not sure if this is the correct approach.
Any advice would be helpful,
Thanks.
