I need to figure out the ice load on some netting but am getting a nnumber that can't be correct. The equations are straight forward. ASCE 7-10 by the way.
t = 0.5"
Vc = 30 mph
temperature = 15 degrees Farenheit
Kzt = 1.0
Ii = 1.0
Dc = .0945 in.
Per 10.4-4
fz= 0.980
Per 10.4-5
td = .98 inches
This seems pretty consrevative to me since we only get a few freezing days per year.
Per 10.4-1
Ai = 3.3 in2
This seems way to high. After mutliplying 0.7 to get to ASD in corresponds to roughly .86 inch thickness of ice.
Anybody see something wrong with my calcs?
KGH
t = 0.5"
Vc = 30 mph
temperature = 15 degrees Farenheit
Kzt = 1.0
Ii = 1.0
Dc = .0945 in.
Per 10.4-4
fz= 0.980
Per 10.4-5
td = .98 inches
This seems pretty consrevative to me since we only get a few freezing days per year.
Per 10.4-1
Ai = 3.3 in2
This seems way to high. After mutliplying 0.7 to get to ASD in corresponds to roughly .86 inch thickness of ice.
Anybody see something wrong with my calcs?
KGH