senthil83
Mechanical
- Jun 26, 2012
- 66
HI
I AM USING ASME STS-1 2011 CODE FOR THE DESIGN OF 50M STEEL CHIMNEY, WHILE CALCULATING THE DESIGN WIND FORCE AS PER
EQN 4.2
WZ = ( CF * qZ*d)/(12(1+6.8iZ))
WZ = ( 0.653 * 34.816 * 8)/ (12(1+(6.8*0.1712))) = 6.99 LBS/FT
WHICH IS VERY LESS COMPARED TO THEIR EXAMPLE CALCULATION IN APPENDIX -E.
PLZ CLARIFY HOW THE WIND FORCE LBS/FT IS COMING VERY LESS. I AM MISSING ANYTHING IN CALCULATION?
THANKS
SENTHIL KUMAR.B
I AM USING ASME STS-1 2011 CODE FOR THE DESIGN OF 50M STEEL CHIMNEY, WHILE CALCULATING THE DESIGN WIND FORCE AS PER
EQN 4.2
WZ = ( CF * qZ*d)/(12(1+6.8iZ))
WZ = ( 0.653 * 34.816 * 8)/ (12(1+(6.8*0.1712))) = 6.99 LBS/FT
WHICH IS VERY LESS COMPARED TO THEIR EXAMPLE CALCULATION IN APPENDIX -E.
PLZ CLARIFY HOW THE WIND FORCE LBS/FT IS COMING VERY LESS. I AM MISSING ANYTHING IN CALCULATION?
THANKS
SENTHIL KUMAR.B