anolan23
Mechanical
- Apr 29, 2015
- 54
Designing a vessel to Section VIII Div. 1 and I need to calculate the pressure rating of this component.
It says in B16.11 that the pressure rating shall be computed as straight seamless pipe of equivalent material.Straight pipe MAWP is calulated in Section VIII Div.1 under UG-27 where it breaks it down to Circumferential Joint and Longitudinal Joint.
I'm having trouble calculating the Longitudinal Joint maximum allowable pressure rating. The formaula is:
P=2SEt/R-0.4t
E= joint efficiency = 0.70
S=max allowable stress = 14020psi
t= minimum required thickness of shell = 0.301in
R=inside radius of shell = 0.119in
The value for P im getting is -4,220,020psi because the thickness is a little bigger than the inside radius. The plug is a 1/2" hex head 3000# F316 - SA-182 so I chose 0.84in for the OD for the equivalent pipe. Am I missing something? I'm trying to get the MAWP for this plug component.
It says in B16.11 that the pressure rating shall be computed as straight seamless pipe of equivalent material.Straight pipe MAWP is calulated in Section VIII Div.1 under UG-27 where it breaks it down to Circumferential Joint and Longitudinal Joint.
I'm having trouble calculating the Longitudinal Joint maximum allowable pressure rating. The formaula is:
P=2SEt/R-0.4t
E= joint efficiency = 0.70
S=max allowable stress = 14020psi
t= minimum required thickness of shell = 0.301in
R=inside radius of shell = 0.119in
The value for P im getting is -4,220,020psi because the thickness is a little bigger than the inside radius. The plug is a 1/2" hex head 3000# F316 - SA-182 so I chose 0.84in for the OD for the equivalent pipe. Am I missing something? I'm trying to get the MAWP for this plug component.