spdracer22
Automotive
- Feb 16, 2005
- 32
This makes sense in my head, but I just wanted to bounce it off you guys to make sure it's correct.
With a sliding caliper, the piston pushes the pad it is in direct contact with against the rotor. Then, once it's contacted, the caliper body slides until the other pad is in contact with the rotor. This leads me to believe that since the piston is essentially pushing in two directions that it should be treated as a 2-pot for calculations; if it were treated as a one pot, there would essentially be only one force, on one side of the rotor.
Anyway...let me know...
With a sliding caliper, the piston pushes the pad it is in direct contact with against the rotor. Then, once it's contacted, the caliper body slides until the other pad is in contact with the rotor. This leads me to believe that since the piston is essentially pushing in two directions that it should be treated as a 2-pot for calculations; if it were treated as a one pot, there would essentially be only one force, on one side of the rotor.
Anyway...let me know...