swazimatt
Civil/Environmental
- Aug 19, 2009
- 242
I would just like to get some clarification on calculating peak flows in a residential township.
the average annual daily demand is 1200l/d
now if the instantaneous peak factor of 5 is used, does this mean that the flow rate at peak demand will be:
1200x5/(24x60x60)=0.09 l/s
seems a bit low, should i assume that the water usage will only be for 12hours instead of the 24 that i used for the calc?
thanks
the average annual daily demand is 1200l/d
now if the instantaneous peak factor of 5 is used, does this mean that the flow rate at peak demand will be:
1200x5/(24x60x60)=0.09 l/s
seems a bit low, should i assume that the water usage will only be for 12hours instead of the 24 that i used for the calc?
thanks