Calculating Total Electric Power Input kW 3 phase Motor 1

[Iomcube]

I am attaching motor nameplate (its an Cl2 compressor)


The running ampere on the meter (it varies with throughput) is now 320A

According to this post (https://www.eng-tips.com/threads/actual-work-380v-vs-460v.91809/post-344509) , total electric kW input will be

=1.732 x 320 Amp x 380 Volt x 1 kW / 1000 W = 210 kW

& if I multiple it by 24 hr I can get kWh

The problem is that nameplate shows a rated power of 185 kW however mine calculate answer is higher than this?

From another source I am quoting this

If the machine is 380 V rated it means that it had a rated phase to neutral voltage of 220 V.

So this means the correct answer will be
=320 Amp x 380 Volt x 1 kW / 1000 W = 121.6 kW

 

[waross]

380V x 1.73 x .0.87 x 0.959 x 320A / 1000 = 148 kW Actual Mechanical Power Out
380V x 1.73 x .0.87 x 0.959 x 336.9A / 1000 = 185 kW Maximum Rated Mechanical Power Out
380V x 1.73 x .0.87 x 336.9A / 1000 = 193 kW Maximum Electrical Power In.

 

[MintJulep]

Power factor (cos(theta)) is given as 0.87.

210 * 0.87 = 182

 

[Iomcube]

@waross

380V x 1.73 x 320A / 1000 = 210.4 kW Actual Electrical Power In ??